Solve -49x² - 19x + 68 = 0


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You have come to the correct place if you are looking to solve the quadratic equation negative 49x squared minus 19x plus 68 equals 0, also known as -49x² - 19x + 68 = 0. Below, we walk you through how to find the answer.

To find the two possible answers to -49x^2 - 19x + 68 = 0, we will start by rewriting the equation in factored form. Then, we will create two separate equations that we can use to solve -49x² - 19x + 68 = 0.

Below is negative 49x squared minus 19x plus 68 in factored form. As you can see, -49x² - 19x + 68 has been grouped into two sets of parentheses.

-(x - 1)(49x + 68)

Next, we set each set of parentheses equal to 0 and solve for x to get the two answers to -49x^2 - 19x + 68 = 0.

(x - 1) = 0
x1 = 1

(49x + 68) = 0
x2 = -1 19/49


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