Solve -66x² + 41x + 80 = 0

You have come to the correct place if you are looking to solve the quadratic equation negative 66x squared plus 41x plus 80 equals 0, also known as -66x² + 41x + 80 = 0. Below, we walk you through how to find the answer.

To find the two possible answers to -66x^2 + 41x + 80 = 0, we will start by rewriting the equation in factored form. Then, we will create two separate equations that we can use to solve -66x² + 41x + 80 = 0.

Below is negative 66x squared plus 41x plus 80 in factored form. As you can see, -66x² + 41x + 80 has been grouped into two sets of parentheses.

-(11x - 16)(6x + 5)

Next, we set each set of parentheses equal to 0 and solve for x to get the two answers to -66x^2 + 41x + 80 = 0.

(11x - 16) = 0
x₁ = 1 5/11

(6x + 5) = 0
x₂ = -5/6

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