You have come to the correct place if you are looking to solve the quadratic equation 10x squared plus 47x minus 57 equals 0, also known as 10x² + 47x - 57 = 0. Below, we walk you through how to find the answer.
To find the two possible answers to 10x^2 + 47x - 57 = 0, we will start by rewriting the equation in factored form. Then, we will create two separate equations that we can use to solve 10x² + 47x - 57 = 0.
Below is 10x squared plus 47x minus 57 in factored form. As you can see, 10x² + 47x - 57 has been grouped into two sets of parentheses.
(x - 1)(10x + 57)
Next, we set each set of parentheses equal to 0 and solve for x to get the two answers to 10x^2 + 47x - 57 = 0.
(x - 1) = 0
x1 = 1
(10x + 57) = 0
x2 = -5 7/10
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