Solve 42x² - 80x + 38 = 0

You have come to the correct place if you are looking to solve the quadratic equation 42x squared minus 80x plus 38 equals 0, also known as 42x² - 80x + 38 = 0. Below, we walk you through how to find the answer.

To find the two possible answers to 42x^2 - 80x + 38 = 0, we will start by rewriting the equation in factored form. Then, we will create two separate equations that we can use to solve 42x² - 80x + 38 = 0.

Below is 42x squared minus 80x plus 38 in factored form. As you can see, 42x² - 80x + 38 has been grouped into two sets of parentheses.

(2x - 2)(21x - 19)

Next, we set each set of parentheses equal to 0 and solve for x to get the two answers to 42x^2 - 80x + 38 = 0.

(2x - 2) = 0
x₁ = 1

(21x - 19) = 0
x₂ = 19/21

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