Solve 80x² + 41x - 84 = 0


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You have come to the correct place if you are looking to solve the quadratic equation 80x squared plus 41x minus 84 equals 0, also known as 80x² + 41x - 84 = 0. Below, we walk you through how to find the answer.

To find the two possible answers to 80x^2 + 41x - 84 = 0, we will start by rewriting the equation in factored form. Then, we will create two separate equations that we can use to solve 80x² + 41x - 84 = 0.

Below is 80x squared plus 41x minus 84 in factored form. As you can see, 80x² + 41x - 84 has been grouped into two sets of parentheses.

(5x - 4)(16x + 21)

Next, we set each set of parentheses equal to 0 and solve for x to get the two answers to 80x^2 + 41x - 84 = 0.

(5x - 4) = 0
x1 = 4/5

(16x + 21) = 0
x2 = -1 5/16


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